# Problem 48

Solution to Problem 48. Written in Python.

Problem: The series, 1^{1} + 2^{2} + 3^{3} + … + 10^{10} = 10405071317. Find the last ten digits of the series, 1^{1} + 2^{2} + 3^{3} + … + 1000^{1000}.

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Solution to Problem 48. Written in Python.

Problem: The series, 1^{1} + 2^{2} + 3^{3} + … + 10^{10} = 10405071317. Find the last ten digits of the series, 1^{1} + 2^{2} + 3^{3} + … + 1000^{1000}.